waecmaths question:
Simplify: $10\tfrac{2}{5}-6\tfrac{2}{3}+3$
Option A:
$6\tfrac{4}{15}$
Option B:
$6\tfrac{11}{15}$
Option C:
$7\tfrac{4}{15}$
Option D:
$7\tfrac{11}{15}$
waecmaths solution:
$\begin{align} & 10\tfrac{2}{5}-6\tfrac{2}{3}+3=\tfrac{52}{5}-\tfrac{20}{3}+\tfrac{3}{1} \\ & =\tfrac{152-100+45}{15} \\ & =\tfrac{97}{15} \\ & =6\tfrac{7}{15} \end{align}$
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